This is a companion discussion topic for the original entry at https://toph.co/p/proper-leap-years

This is a companion discussion topic for the original entry at https://toph.co/p/proper-leap-years

Learn to Google.

However, methode to determine a leap year is simple.

- The year have to be evenly divided by 4
not by 100.**but** - However, the year which is evenly divided by 400 is always a leap year.

What’s wrong with my code here ?

C++

```
#include <stdio.h>
int main()
{
int x;
scanf("%d",&x);
if(x%4 ==0){
printf("Yes");
}
if(x%100 == 0 && x%400 == 0){
printf("Yes");
}
else printf("No");
return 0;
}
I'm getting wrong answer on the last test case here. The Gregorian criteria says It's a leap year if :
"The year can be evenly divided by 4;
If the year can be evenly divided by 100, it is NOT a leap year, unless;
The year is also evenly divisible by 400. Then it is a leap year."
```

Nevermind i fixed out. Did not understand the statement before.

#include <stdio.h>

int main()

{

int x;

scanf("%d",&x);

if(x%4 ==0 && x%100 !=0){

printf(“Yes”);

}

else if(x%400 == 0){

printf(“Yes”);

}

```
else printf("No");
return 0;
```

}

This one worked, so it’ll be a leap year ALWAYS if it is evenly divided by 400. and it’ll also be a leap year if it is evenly divided by 4 and also not evenly divided by 100

y=int(input())

if y%4==0 and y%100!=0:

print(‘yes’)

elif y%400==0 :

print(‘yes’)

else :

print(‘no’)

whats wrong?

1 Like

Please check your “yes” and “no”…