Is It a Perfect Square?

Given some numbers, can you tell, if the product of these numbers are a perfect square or not? A num…

Click here to read the complete problem statement.


If you need help solving this problem, mention your approach and ask specific questions. Please avoid sharing your code and asking the Community to figure out “what’s wrong”.

#include<bits/stdc++.h>
using namespace std;
int main()
{
int x,y,z,i,j;
cin>>x;
for(i=0;i<x;i++)
{
int count=0;
cin>>y;
for(j=0;j<y;j++)
{
cin>>z;
int a=sqrt(z);
if(z-(a*a)==0)
count++;
}
if(count==y)
cout<<“YES”<<endl;
else
cout<<“NO”<<endl;
}

}
what’s the problem this code?

This problem has some problems. I think the processing algorithm is not correct.

Code

Can anyone tell me what is wrong with the code?
It seems to be outputting the wrong answer on test 2``

#include<bits/stdc++.h>
#define pi 3.141592653589
using namespace std;

int main()
{
int t,n,c=0,a[1000];
double div,m;
cin >> t;
while(t–)
{
cin >> n;
for(int i=0;i<n;i++)
{
cin >> a[i];
m=sqrt(a[i]);
div=a[i]/m;
if(m!=(int)div)
{
c++;
break;
}
}
if(c!=0)cout<<“NO”<<endl;
else cout<<“YES”<<endl;
c=0;div=0;m=0;
}
}

What is problem??
2th test case Runtime Error

#include<stdio.h>
int main()
{
long long int T,i,n,j,l;
scanf(“%lld”,&T);
for(i=1; i<=T; i++){

    scanf("%lld",&n);
long long int m=1,h;
        double k,l;
    for(j=1; j<=n; j++){
        scanf("%lld",&h);
        m=m*h;
    }
    k=sqrt(m);
    l=m-(k*k);
    if(l==0){
        printf("YES\n");
    }
    else{
        printf("NO\n");
    }

}

}
After running it,with the sample cases my compiler says YES NO NO but toph says YES NO YES.How is it possible ??? Plz, hlp.
Matha gorom hoye jacche. Continuously 4 days I have noticed that kind of problem in different kinds of problems in toph.co