Circles in a Rectangle

Limits: 1s, 131 MB

Two circles are placed inside a rectangle. They do not intersect each other but they are touching each other. They both have the same radius. Each side of the rectangle are also touched by the circles.

This is a companion discussion topic for the original entry at

#include <stdio.h>

int main() {
int T,x,i;
float r,pi=3.1416,A;
printf(“Case %d: %.2f\n”,x,A);


return 0;


what’s wrong with this code?
this is telling that case 3: 12638.46 but in my code it’s telling 12638.47.why?

//um passing time with the chili sauce
using namespace std;
#define io_fast() ios :: sync_with_stdio(false); cin.tie(0);
#define go return 0
#define ll long long int
#define ull unsigned long long int
#define ld long double
#define vi vector
#define vl vector
#define vc vector
#define vs vector
#define vp vector< pair<ll,ll> >
#define sl set
#define sc set
#define pi 2*acos(0.0)

int main()
float t,r,m,p;
int d=1;
printf(“Case %d: %.2f\n”,d++,m);
whats the pb?it cannt pass the testcase

@dipto98 Bro, can you provide the 4th test case? My code is failing at 4th tc.

u have to find out the area of the rectangle and area of two circle…then simply substraction of them

is there a figure provided ? cause i’m not seeing any green area there…strong text

I can’t even see any figure


#include <stdio.h>

int main(void)
    float pi = 3.1416;
    int n;
    scanf("%d", &n);
    float ar[n];
    for (int i = 0; i < n; i++)
        scanf("%f", &ar[i]);

    float result[n];
    for (int i = 0; i < n; i++)
        float a = ar[i] * 2;
        float b = a * 2;
        float rectangleArea = a * b;
        float circlesArea = 2 * (pi * (ar[i] * ar[i]));
        float area = rectangleArea - circlesArea;
        result[i] = area;
    for (int i = 0; i < n; i++)
        printf("%0.2f\n", result[i]);

    return 0;

what’s wrong with this code?