# BigNumSum

You will be given two numbers of 40 digits each. You will have to print the summation of these two n…

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What’s the problem?

``````
#include<set>
#include<iostream>
#include<vector>
#include<algorithm>
#include<stack>
#include<climits>
#include<cstring>
#include<cmath>
#include<unordered_map>
#include<sstream>
#include<cmath>
#include<iomanip>
#include<numeric>
using namespace std;

int main(){
string a,b;
cin>>a>>b;
vector<int> v1;
vector<int> v2;
for(int i=0;i<a.size();i++){
v1.push_back(a[i]-'0');
v2.push_back(b[i]-'0');
}
int s=0;
string res="";
for(int i=v1.size()-1;i>=0;i--){
int sum=v1[i]+v2[i]+s;
if(sum>=10){
string r=to_string(sum);
res+=r;
s=r-'0';
}
else{
string x=to_string(sum);
res+=x;
s=0;
}
}
reverse(res.begin(),res.end());
cout<<res;
}``````

Bro, test it for 98 + 102 ( not 102 + 98).

I have got AC before bro…by the way thanks for responding Java donot use Bigint