Mysterious Sum

Sohel vai reads newspaper every morning. The newspaper he reads contains some good features includin…

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If you need help solving this problem, mention your approach and ask specific questions. Please avoid sharing your code and asking the Community to figure out “what’s wrong”.

#include <iostream>
using namespace std;

int main() {
	unsigned int i,t,a,b,sum;
	cin>>t;
	for(i=1;i<=t;i++){
		cin>>a>>b;
		if(a<=100&&b<=100){
		sum=10*(a+b)+(a-b);
		cout<<"Case "<<i<<": "<<sum<<endl;
		}
	}
	return 0;
}

t=int(input())
for i in range(1,t+1):
a,b=[int(x) for x in input().split()]
sum=10*(a+b)+(a-b)
print(“Case {}: {}”.format(i,sum))
both says second test case wrong answer

It is because your solve is incorrect.
Read the problem statement carefully and try to figure out the mystry of the sum yourself.

#include<bits/stdc++.h>
using namespace std;
int main(){
    int t,a,b,c,d;
    cin>>t;
    for(int i=1;i<=t;i++){
        cin>>a>>b;
        c=a+b;
        d=a-b;
        cout<<"Case "<<i<<": "<<(c*10)+d<<endl;
    }
}

getting wrong in test case 2?

Your code will be

include<iostream>
#include<math.h>
using namespace std;
int main()
{
    int T,A,B,Sum=0,Sub=0;
    cin>>T;
    for(int i=1;i<=T;i++)
    {
        cin>>A>>B;
        Sum=A+B;
        Sub=A-B;
        cout<<"Case "<<i<<": "<<Sum<<Sub<<endl;
    }

}

Where is the problem in my code?
#include<stdio.h>
#inculde<math.h>
int main()
{
int T;
scanf(“%d”,&T);
for ( int i=1;i<=T;i++){
int N,M;
scanf(“%d %d”,&N,&M);
int Sum=N+M;
int Count =(Sum*10)+(N-M);
printf(“Case %d: %d”,i,Count);
}
return 0;
}